gcc-bufdata-integrating2text
Integrating C Buffer Data Into the instruction of .text
segment instead of on .data
, .rodata
to avoid copy.
Usage
In your C code, invoke INLINE_DATA_GEN(var_name, data)
and use this preprocessor to replace it.
Both var_name
and data
don't need quotation marks. For detail, please check example.
Example
Example in test/
.
test.c:
#include <stdio.h>
int main(){
INLINE_DATA_GEN(buf, \x00\x01\x02aabbccjbinisdaf8wefwe322111hhh);
printf(buf);
}
test_processed.c:
#include <stdio.h>
int main(){
__attribute__ ((aligned (1))) char
buf_32[] = {104},
buf_28[] = {49, 49, 104, 104},
buf_24[] = {51, 50, 50, 49},
buf_20[] = {101, 102, 119, 101},
buf_16[] = {97, 102, 56, 119},
buf_12[] = {110, 105, 115, 100},
buf_8[] = {99, 106, 98, 105},
buf_4[] = {97, 98, 98, 99},
buf_0[] = {0, 1, 2, 97}
;
char* buf = buf_0;
printf(buf);
}
test_processed.s:
.file "test_processed.c"
.text
.globl main
.type main, @function
main:
.LFB0:
.cfi_startproc
endbr64
pushq %rbp
.cfi_def_cfa_offset 16
.cfi_offset 6, -16
movq %rsp, %rbp
.cfi_def_cfa_register 6
subq $64, %rsp
movq %fs:40, %rax
movq %rax, -8(%rbp)
xorl %eax, %eax
movb $104, -41(%rbp)
movl $1751658801, -40(%rbp)
movl $825373235, -36(%rbp)
movl $1702323813, -32(%rbp)
movl $2000184929, -28(%rbp)
movl $1685285230, -24(%rbp)
movl $1768057443, -20(%rbp)
movl $1667392097, -16(%rbp)
movl $1627521280, -12(%rbp)
leaq -12(%rbp), %rax
movq %rax, -56(%rbp)
movq -56(%rbp), %rax
movq %rax, %rdi
movl $0, %eax
call printf@PLT
movl $0, %eax
movq -8(%rbp), %rdx
xorq %fs:40, %rdx
je .L3
call __stack_chk_fail@PLT
.L3:
leave
.cfi_def_cfa 7, 8
ret
.cfi_endproc
.LFE0:
.size main, .-main
.ident "GCC: (Ubuntu 9.3.0-17ubuntu1~20.04) 9.3.0"
.section .note.GNU-stack,"",@progbits
.section .note.gnu.property,"a"
.align 8
.long 1f - 0f
.long 4f - 1f
.long 5
0:
.string "GNU"
1:
.align 8
.long 0xc0000002
.long 3f - 2f
2:
.long 0x3
3:
.align 8
4:
It's easy to find that the buffer data aren't stored in the .data
or .rodata
segment.